Fix Over Lapping Dates

  • I have some records that have over lapping dates. I need to end date them in such a way to fix

    over lapping dates. See example and expected results.

    declare @overlap table

    (

    ID int identity,

    infoname char(10),

    code char(10),

    mods char(30),

    type varchar(30),

    effective date ,

    termination date

    )

    insert into @overlap

    select 'DUMMY','99205','C','*','01/01/2008','12/31/2100'

    insert into @overlap

    select 'DUMMY','99205','C','*','01/01/2009','12/31/2100'

    insert into @overlap

    select 'DUMMY','99205','C','*','01/01/2010','12/31/2100'

    insert into @overlap

    select 'DUMMY','99206','x','*','01/01/2011','12/31/2100'

    insert into @overlap

    select 'DUMMY','99206','x','*','01/01/2012','12/31/2100'

    insert into @overlap

    select 'DUMMY','99206','x','*','01/01/2013','12/31/2100'

    SELECT * FROM @OVERLAP

    /*

    ---------------------------

    ---- expected results----

    ---------------------------

    1 DUMMY 99205 C * 2008-01-01 2008-12-31

    2 DUMMY 99205 C * 2009-01-01 2009-12-31

    3 DUMMY 99205 C * 2010-01-01 2100-12-31 <-unchanged

    4 DUMMY 99206 x * 2011-01-01 2011-12-31

    5 DUMMY 99206 x * 2012-01-01 2012-12-31

    6 DUMMY 99206 x * 2013-01-01 2100-12-31 <-unchanged

    */

  • This little snippet produces your desired output.

    ;with cte as

    (

    Select code, effective, termination,

    row_number() over (partition by code order by effective desc) rowNum

    from @overlap

    )

    UPDATE cte set

    termination = cast(cast(year(effective) as char(4)) + '-12-31' as date)

    FROM cte

    WHERE rowNum > 1;

    SELECT * from @overlap

    There are probably a dozen different and very clever ways to use dateadd, datediff, etc. . . to get your desired results.

    You can also pick the termination date apart with some other date functions if you don't want to use the literals.

    This should get you going in the right direction.

    __________________________________________________________________________________________________________
    How to Post to get the most: http://www.sqlservercentral.com/articles/Best+Practices/61537/

  • Quick and simple solution with LEAD()

    😎

    USE tempdb;

    GO

    SET NOCOUNT ON;

    declare @overlap table

    (

    ID int identity,

    infoname char(10),

    code char(10),

    mods char(30),

    type varchar(30),

    effective date ,

    termination date

    )

    insert into @overlap

    select 'DUMMY','99205','C','*','01/01/2008','12/31/2100'

    insert into @overlap

    select 'DUMMY','99205','C','*','01/01/2009','12/31/2100'

    insert into @overlap

    select 'DUMMY','99205','C','*','01/01/2010','12/31/2100'

    insert into @overlap

    select 'DUMMY','99206','x','*','01/01/2011','12/31/2100'

    insert into @overlap

    select 'DUMMY','99206','x','*','01/01/2012','12/31/2100'

    insert into @overlap

    select 'DUMMY','99206','x','*','01/01/2013','12/31/2100'

    SELECT

    OL.ID

    ,OL.infoname

    ,OL.mods

    ,OL.type

    ,OL.effective

    ,LEAD(DATEADD(DAY,-1,OL.effective),1,OL.termination) OVER

    (

    PARTITION BY OL.mods

    ORDER BY OL.effective

    ) AS termination

    FROM @OVERLAP OL

    ;

    Output

    ID infoname mods type effective termination

    --- ---------- ----- ----- ---------- -----------

    1 DUMMY C * 2008-01-01 2008-12-31

    2 DUMMY C * 2009-01-01 2009-12-31

    3 DUMMY C * 2010-01-01 2100-12-31

    4 DUMMY x * 2011-01-01 2011-12-31

    5 DUMMY x * 2012-01-01 2012-12-31

    6 DUMMY x * 2013-01-01 2100-12-31

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