RE: Question of the Day for 22 Jan 2004
It seems to me that there is only one right answer and that would be SELECT * FROM #test1 WHERE col1 LIKE '%5[%]%' The reason is because the query should return a row with the value 5% in col1. But suppose you have the value fjf5j%fjf in col1. SELECT * FROM #test1 WHERE col1 LIKE […]
2004-01-22