December 14, 2001 at 9:07 am
I've been struggling with this for a while. I imagine the answer requires a few temporary tables, but does anyone else have a more elegant solution?
I have a table with four fields in it. The fourth field contains duplicate values. I want to insert into a new table just the values in the fourth field that have a duplicate value (and ignore values that appear just once).
For instance, if my source table is like this:
data1, data2, data3, data4
data1, data5, data6, data7
data2, data6, data1, data4
data3, data3, data5, data9
data2, data5, data3, data7
The new table will look like this:
data4
data7
Any brilliant ideas out there?
December 14, 2001 at 9:53 am
Not really brilliant, but this may work:
create table MyTest
( MyChar varchar( 10)
, MyChar2 varchar( 10)
, MyChar3 varchar( 10)
, MyChar4 varchar( 10)
)
go
insert MyTest select 'data1', 'data2', 'data3', 'data4'
insert MyTest select 'data1', 'data5', 'data6', 'data7'
insert MyTest select 'data2', 'data6', 'data1', 'data4'
insert MyTest select 'data3', 'data3', 'data5', 'data9'
insert MyTest select 'data2', 'data5', 'data3', 'data7'
go
select * from MyTest
go
select MyChar4
from MyTest
group by MyChar4
having count(*) > 1
go
drop table MyTest
Steve Jones
Follow me on Twitter: http://www.twitter.com/way0utwest
Forum Etiquette: How to post data/code on a forum to get the best help
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January 3, 2002 at 6:06 am
A very simple solution that works perfectly! In my opinion, that makes it brilliant!
Many thanks for your help Steve.
January 3, 2002 at 9:45 am
You're welcome and hope it helps.
Steve Jones
Follow me on Twitter: http://www.twitter.com/way0utwest
Forum Etiquette: How to post data/code on a forum to get the best help
My Blog: www.voiceofthedba.com
January 23, 2010 at 4:53 am
br_beneficiarysurname br_dob br_servicepointcode br_beneficiaryid br_dateofregistration br_visitdate row
G 8/27/1944 SP3139010 T0301390007958300242 8/27/2009 8/27/2009 2
G 8/27/1944 SP3139010 T0301390007958300240 8/27/2009 8/27/2009 3
iam getting all duplicate using this query but i didi not got this only two duplicates but there are three duplicates.
with Duplicaterecords as
(
select br_beneficiarysurname,br_dob,br_districtid,br_servicepointcode,br_beneficiaryid,br_dateofregistration,br_visitdate,
row_number() over(partition by br_districtid,br_dob,br_servicepointcode order by br_districtid,br_dob,br_servicepointcode) as row from TELEMONITORING.beneficiaryregistration
where br_beneficiarytypeid=3
)
select * from Duplicatecalls
where row>1
order by br_servicepointcode
Malleswarareddy
I.T.Analyst
MCITP(70-451)
January 23, 2010 at 5:26 am
@ malleswarareddy_m:
Seems like your question is similar to your other thread : So, please don't cross post.
January 23, 2010 at 7:05 am
ok but this is my exact query and i do not cross apply.because this post is some what matching my requirement but not full fledged.
the above post is my query.
because i ugently needed this report.by the above query i got duplicate there are 3 duplcate but i will get only 2 duplicate by the above query.
Thanks
Malleswarareddy
I.T.Analyst
MCITP(70-451)
January 23, 2010 at 7:07 am
You have a thread for your question already, don't hijack other people's threads.
Gail Shaw
Microsoft Certified Master: SQL Server, MVP, M.Sc (Comp Sci)
SQL In The Wild: Discussions on DB performance with occasional diversions into recoverability
January 23, 2010 at 7:11 am
ok i did not hijack others thraed
but this is my urgent requirement report in company.
so i posted here understanding me
ok sorry.
Malleswarareddy
I.T.Analyst
MCITP(70-451)
January 23, 2010 at 11:23 am
malleswarareddy_m (1/23/2010)
ok i did not hijack others thraedbut this is my urgent requirement report in company.
so i posted here understanding me
ok sorry.
As a side bar, any time something is "urgent", take the time to help others help you. Do like I said on the other thread and read/heed the following article. People will jump through flaming hoops for you if you post data in a readily consumable format like the article suggests.
http://qa.sqlservercentral.com/articles/Best+Practices/61537/
--Jeff Moden
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