Leap Year got Me ... Help!
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On 1 January we were trying to pull in our normal 7 day load (7 Days) and it pulled one too may days. We believe it is due to leap year last year. What did I do wrong? Can someone give me a good set of code for leap year?
declare @i_to_day int
declare @i_to_year int
declare @str_to_day varchar(3)
declare @str_to_year varchar(2)
select @current_max = max(dateprocessed) from table1
---- PULL JULIAN DATE ... YY, DDD
select @i_to_year = convert(int,substring(@current_max,2,2))
select @i_to_day = convert(int,substring(@current_max,4,3))
select @i_to_day = @i_to_day + 8
if @i_to_day > 365 -- means that the start day was in the previous year if we are adding 7 days
begin
select @i_to_year = @i_to_year + 1
select @i_to_day = @i_to_day % 365
end
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IF ISDATE(CAST(DATEPART(YEAR, GETDATE()) AS CHAR(4)) + '-02-29') = 1
BEGIN
PRINT 'Leap year'
END
ELSE
BEGIN
PRINT 'Not a leap year'
END
Good Hunting!AJ Ahrens
webmaster@kritter.net -
We work with a date range so need to go by julian date ... can I say if it is 366 only add 7 days rather than 8?
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I'm sure you can. The code sample I provided is just 1 way of attempting to ID if the year is a leap year or not. The meat of the code would be where you add 7 OR 8...
Good Hunting!AJ Ahrens
webmaster@kritter.net
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