Viewing 2 posts - 1 through 2 (of 2 total)
This also count every row
SELECT COUNT(coalesce([Name],'')) AS [COUNT(*) This is 8 too] FROM [CountTest];
January 30, 2015 at 2:21 am
#1774271
Thank you all.
Your replies are precious.
January 23, 2012 at 6:40 am
#1437054