Split string using multiple delimiters - version 2

CREATE FUNCTION dbo.fn_generate_numbers_v2
(@NumRows INT)
RETURNS @returnTable TABLE (RowNum INT PRIMARY KEY)
AS
BEGIN

DECLARE @idt INT
SET @idt = 0
WHILE (@idt < @NumRows)
BEGIN
	SELECT @idt = @idt + 1
	INSERT INTO @returnTable
		SELECT @idt
END
RETURN
END
GO


CREATE FUNCTION dbo.[fn_split_string_using_multiple_delimiters_v2]
(
      @String    VARCHAR(MAX),  -- input string
      @delimiter VARCHAR(32)    -- delimiter list 
)
RETURNS @Table TABLE(rowid INT IDENTITY PRIMARY KEY,        
items VARCHAR(MAX)
)
BEGIN
 
        DECLARE @Xml AS XML
        DECLARE @derived_string VARCHAR(MAX)
 
        ;WITH N1 (n) AS (
			SELECT RowNum AS [n] FROM dbo.fn_generate_numbers_v2(len(@String))
		)
	
        SELECT @derived_string=STUFF((SELECT '' + (Case When
                PATINDEX('%[' + @delimiter + ']%',SUBSTRING(@String,Nums.n,1)) >0
                Then ',' else LTRIM(RTRIM(SUBSTRING(@String,Nums.n,1))) end)
        FROM N1 Nums WHERE Nums.n<=LEN(@String)  FOR XML PATH('')),1,0,'')
 
        SET @Xml = cast(('<a>'+replace(@derived_string,
                ',','</a><a>')+'</a>') AS XML)
 
        INSERT INTO @Table SELECT DISTINCT REPLACE(A.value('.', 'VARCHAR(MAX)'),CHAR(13)+CHAR(10),'')
                as [Column] FROM @Xml.nodes('a') AS FN(a)
 
RETURN
END
GO


select * from [fn_split_string_using_multiple_delimiters_v2](
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